quick question about generating 5 random charcters and displaying 5 lines

make your i in the forloop go from 1 to less than 26

Insert

if(i%5==0) // % is the modulo operator
cout <<endl;

after your cout << ch; statement, it will output a new line after every five chars

i got a function which is called "void create (int n)" from the class as follow:

void Database::create(int n)
{
numRecord = n;
Record *pH, *pT, *pL;
int i;
pH = new Record;
pL = pH;
pL->setName('\0');
for (i=1; i<n; i++)
{
pT = new Record;
pL->setNext(pT);
pL = pT;
pL->setName();
}
pFirst = pH;
}

I want to create n records and each record contains a name of 5 random characters. How can i do that?? Please help
Thank you!!
Dicky

i have re-write the programme again, the code is shown as follow:
The first class as following:
class Record
{
private:
char name[6];
Record *pNext;
public:
Record()
{
pNext = 0;
}
void setName(char *nm)
{
strncpy_s (name,nm,5);
name[5] = '\0';
}
char * getName()
{
return name;
}
void setNext(Record *pC)
{
pNext = pC;
}
Record * getNext()
{
return pNext;
}
};
The second class as follow:
#include "Record.h"
class Database
{
private:
Record *pFirst;
int numRecord;
public:
Database();
~Database();
void create(int n);
char *genName();
void display();
bool remove(char * recName);
bool insert(int pos, Record *rec);
};
The implementation of the above class as following:
#include <iostream>
#include "Database.h"
#include <time.h>
using namespace std;
Database::Database()
{
srand((unsigned int) time(NULL));
numRecord = 0;
pFirst = 0;
}
Database::~Database()
{;}
void Database::create(int n)
{
numRecord = n;
Database *re = new Database;
Record *pH, *pT, *pL;
int i;
pH = new Record;
pL = pH;
pL->setName(re->genName());
for (i=1; i<n; i++)
{
pT = new Record;
pL->setNext(pT);
pL = pT;
pL->setName(re->genName());
}
pFirst = pH;
}
char * Database::genName()
{
int ch;
char *pf = new char;
for (int i=1; i<6; i++)
{
ch = ((rand()%26) + 97);
cout << (char) ch;
if (i%5 == 0)
{
cout << endl;
}
}
return pf;
}
void Database::display()
{
if (pFirst!=0)
{
Record *pTemp = pFirst;
int i=0;
do
{
cout << "Record #" << i << ": " << pTemp->getName() << endl;
pTemp = pTemp->getNext();
i++;
}
while (pTemp!=0);
}
}
bool Database::remove(char *recName)
{
return true;
}
bool Database::insert(int pos, Record *rec)
{
return true;
}
The main is shown as below:
#include <iostream>
#include "Database.h"
using namespace std;
int main()
{
Database db;
db.create(5);
char choice;
do
{
cout << "(i) insert\n";
cout << "(r) remove\n";
cout << "(d) display\n";
cout << "(q) quit\n";
cout << ".........Input?";
cin >> choice;
cout << endl;
switch (choice)
{
int pos1;
case 'i': case 'I':
{
char *name1 = new char;
Record *r = new Record();
cout << "Name of Record? ";
cin >> name1;
cout << "Insert before Record#? ";
cin >> pos1;
r->setName(name1);
db.insert(pos1, r);
}
break;
case 'r': case 'R':
break;
case 'd': case 'D':
{
db.display();
}
break;
}
}
while (!((choice == 'q')||(choice=='Q')));
return 0;
}

The whole programme can be compiled and when i press d for display the records, it doesn't show any random characters which are generated by rand function. The output is shown as below:
Record #0: (random chinese characters)
Record #1: (random chinese characters)
Record #2: (random chinese characters)
Record #3: (random chinese characters)
Record #4: (random chinese characters)

Please help me!!!
Thank you!!
Dicky

But, how do i assign it?? Please give me a hand, please??
Thank you!!
Dicky

its probably my fault, I tend to use raw char arrays for simple tasks and posted the howto make random letters code in that format.

py will need to be a string rather than a char* for the method, as now written, to work. You would have to change the return type AND the declaration of py AND how it is used whereever you used it in your code - a "refactoring" of your code.

Otherwise, use the char* code that I suggested

Your name data field in the record class is a char array. Just keep it that way. So avoid the char* altogether in the

char[] Database::genName()
{
char tempName[5];
for(int i = 0; i < 5; ++i )
{
tempName[i] = (char)((rand()%26) + 97);

}
return tempName;
}

make sure to adjust the datatype in the calling method to expect the char array