output formatting [was: Help!....]

This function seems to meat conditions:

void display()
{
for( int row = 0; row < 10; ++row)
{
for( int col = 0; col < 10; ++col)
{
if(((row % 2) == 0 && (col % 2) == 0) ||
((row % 2) != 0 && (col % 2) != 0))
{
cout << "*";
}
if(((row % 2) == 0 && (col % 2) != 0) ||
((row % 2) != 0 && (col % 2) == 0))
{
cout << "#";
}
}
cout << endl;
}
}

Assignment time again?

I'll give a hint:
You have even and odd lines.
(lineNo % 2) == 0 means even line
(lineNo % 2) == 1 means odd line

Don't forget: you can break out the cout statements into functions...

Rune

Thanks dude...
btw
Don't forget: you can break out the cout statements into functions...
means?... i dun quite understand...

Thanks dude...
btw
Don't forget: you can break out the cout statements into functions...
means?... i dun quite understand...
void printAsterisk()
{
cout << "*";
}

void printPound()
{
cout << "#";
}

void newLine()
{
cout << endl;
}

void printEvenLine()
{
printAsterisk();
printPound();
printAsterisk();
printPound();
printAsterisk();
printPound();
printAsterisk();
printPound();
printAsterisk();
printPound();
newLine();
}

void printOddLine()
{
printPound();
printAsterisk();
printPound();
printAsterisk();
printPound();
printAsterisk();
printPound();
printAsterisk();
printPound();
printAsterisk();
newLine();
}

void main()
{
printEvenLine();
printOddLine();
printEvenLine();
printOddLine();
printEvenLine();
printOddLine();
printEvenLine();
printOddLine();
printEvenLine();
printOddLine();
}
Technically, this meets the requirement, although I'm quite sure it's not what your teacher intended... :D

Rune

*****
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***
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*
how are you gonna make this by use for loop...
can any1 help... ty

I think frozenboy need to work this out by himself. After all, an assignment should be done by the assignee, right?

Hint: A for loop inside a for loop.

Rune

Technically, this meets the requirement, although I'm quite sure it's not what your teacher intended... :D
Rune

ya never know...might get some creativity points. :p