Finding a decimal

just try to save that float number to int and subtract it from that float number and save the result again back to float. Some type conversion mmay be required.

<Math.h> is an old header file which has been replaced by <cmath>..

You should use the fmod() function from <cmath>.. ;)

Ok, so, I was right. It does find the decimal value. I guess I should tell you the program I am making. I am making a factoring program to match the speed of my calculator to my computer (it's actually no match, I know, but I thought it would be fun). Anywho, the program works for some values, but for others, the program closes after it finds some values. Here's the code. Please note that it is probely very messy and has no notes.

#include <iostream>
#include <stdio.h>
#include <cmath>

using namespace std;

long double s = 1;
long double t = 1;
long double u = 1;

int testnum();

int findfrac()
{
long double dec,ff,gg;
gg = 1;

t = s/u;

dec = fmod(t,gg);

if (dec == 0)
{
cout << u << ",\a";
u = u + 1;
}

if (dec != 0)
{
u = u + 1;
}

testnum();
}

int exit()
{
cout << s << "\a";
int po;
cin >> po;
}

int testnum()
{
if (s == u)
{
exit();
}
if (s != u)
{
findfrac();
}

return 0;
}

int main()
{

cout << "Factoring Number: ";
cin >> s;
testnum();
return 0;
}

If anyone has any reasons why the program quits on me, please, do tell.

<Math.h> is an old header file which has been replaced by <cmath>..

You should use the fmod() function from <cmath>.. ;)
How does fmod() solves the purpose.fmod() returns the floating-point remainder of x / y.
It doesn't give the fractional part.

How does fmod() solves the purpose.fmod() returns the floating-point remainder of x / y.
It doesn't give the fractional part.

Yes thats correct.. If you USE fmod() like I said..
It will do what the OP was after..
This function returns the decimal section of a number..
double decimal(double x)
{
return((fmod(x,10))-((int)fmod(x,10)));
}

Im sorry bubbster I dont get what your trying to do.. Can you post up what the output should look like for a certain number?
Thanks mate

I think you all are working too hard, I made this and if I understand what you want it works.

testnum()
{
//test all nums <= s
do{
if(s % u == 0) // %(mod) returns 0 if u divides evenly into s
{
cout << endl << u;
}
}while(u++ <= s);
}

void main()
{
cout << "Enter num: ";
cin >> s;
testnum();

//get input to allow user to see results
cin >> s;

return 0;
}
void main and return 0;...where did you learn that??
use int main

durr woops

void main()

***? Very bad.. :(

Nathan, how does your function testnum() know the value of s?

You dont send it there in any way?

all variables are assumed global as in orig code submitted by bubbster.

if i understand correctly he just wants to show all the factors of a user supplied number (i.e. all numbers that divide evenly in to that number)

Yes they are..

I have no idea why he would do that? :eek: :eek:
yes, not good practice but I just thought I would leave things the way they were as much as possible.

if i understand correctly he just wants to show all the factors of a user supplied number (i.e. all numbers that divide evenly in to that number)

Is that all?

So if you enter 20 the answer is 1, 2, 4, 5, 10..

Is that all?

So if you enter 20 the answer is 1, 2, 4, 5, 10..
and 20.

that would work, except the number to find the factors of must be accepted from the user, it can't be hard-coded.

Of course..
If the OP cant add that, they really shouldnt be here..

No worries mate..

If you would just explain what your after better, we would get there in under 2 pages ;)

so this long winded thread was all about a cin>>x instead of int x=200; ?
oh dear...
I badly wanted to close the thread. :mad:

so this long winded thread was all about a cin>>x instead of int x=200; ?
oh dear...

Yes it was quite painful Danny.. :(

LOL